Mathematics
14 Online
OpenStudy (anonymous):
Medal and fan given for answer!
Determine the vertex, focus, and directrix of the parabola without graphing.
See the equation below:
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[y+(x+2)^2=3\]
OpenStudy (anonymous):
Vertex is easy, how much is y when x=-2
OpenStudy (anonymous):
3
OpenStudy (anonymous):
So what is the vertex?
OpenStudy (anonymous):
(-2,3)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Excellent
OpenStudy (anonymous):
How do you find the focus now?
OpenStudy (anonymous):
Is the parabola concave up or concave down?
OpenStudy (anonymous):
Focus is (0,p) or (p,0) so I need to find p. It is concave down.
OpenStudy (anonymous):
No not (0,p), it is (-2,p)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Oops, that makes sense since it's translated.
OpenStudy (anonymous):
\[
4 \frac 1 4(y-3) =- (x+2)^2
\]
How much is p?
OpenStudy (anonymous):
How did you get 4 (1/4) ?
OpenStudy (anonymous):
To find p the equation must be
\[
4 p(y-y_0)=(x-x_0)^2
\]
we have 1 in front of (y-3) so
\[
1 = 4 \times \frac 14
\]
OpenStudy (anonymous):
How much is p?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
1/4
OpenStudy (anonymous):
ok, since the parabola is concave down, where is the focus?
OpenStudy (anonymous):
(-2,1/4)
OpenStudy (anonymous):
No,\[ (-2,3-\frac 14)\]
OpenStudy (anonymous):
(-2, 11/4)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
The directrix is y= 3+1/4=13/4
OpenStudy (anonymous):
The focus must be on the axis of the parabola
OpenStudy (anonymous):
Did you understand it?
OpenStudy (anonymous):
Yes! Thanks so much.
OpenStudy (anonymous):
YW