is the side opposite the 60 degree angle in a 30-60-90 triangle ALWAYS the square root of 3?
What makes you think that it is?
imagine I had a 30-60-90 triangle with the side opposite the 60 degrees as \(\sqrt{3}\) What would happen if I doubled all the side lengths?
im studying on spark notes and they concluded that, the side was the square root of 3 since it was opposite of the 60 degree angle. I need conformation
It would help if you posted that question here to give us more context
its more of a general question but okay. hold on
What is the area of triangle QRS if RS is tangent to circle Q?
|dw:1417374356730:dw|
ok - so you are ALSO given one of the triangles lengths - in this case the length is 4
so what you have is (if I have read your diagram correctly): |dw:1417374553941:dw|
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