ax + 4b > 9 x > the quantity negative 3 times b minus 5 all over negative a x < the quantity 5 minus 3 times b all over negative a x < the quantity negative 3 times b plus 5 all over negative a x > the quantity negative 3 times b plus 5 all over negative a
@Abhisar
Hey there! Welcome to OpenStudy :)
@TheSmartOne
Thank you @Abhisar
@Abhisar do you mind helping me still. I am still waiting here for help.
Sorry Mathematics is not my forte :(
Oh may you tag someone to help me @Abhisar
@Jhannybean may help you
ax + 4b > 9 Since you're solving for the quantity x, you want to move everything else on to the other side of the \(\gt\) sign
So you'll subtract -4b from both sides of the inequality.
DO that and tell me what you get.
ok hold on
-ax>9 - 4b?
Tell me why you made it negative.
made what negative
Why have you written -ax on the left hand side? you're subtracting -4b from the +4b that is already there. No need to change ax
oh sorry
ax + 4b > 9 - 4b -4b ______________________ ax > 9 - 4b This is what you got, yes?
no wait there is supposed to be a negative in front of ax so it would be -ax I wrote the equation wrong
So your original equation is -ax + 4b > 9 ?
yes
sorry for the confusion my bad
No problem :)
So yes, your previous post would be correct.
ok so now we have to continue
-ax > 9-4b \(\checkmark\)
When you divide or multiply both sides of an inequality by a negative value, you always have to flip the sign. This means \(\gt\) will become \(\lt\)
ok
what will I have to do next?
@Jhannybean
So divide both sides of your inequality by -a, this will flip your inequality. What do you get?
i REALLY DO NOT KNOW i AM CONFUSED
It's ok, it's ok. calm down :)
oh sorry did not mean to use caps I am trying to type without having my eyes on the keyboard
\[\frac{-ax}{-a} \gt \frac{9-4b}{-a}\]Like I mentioned, When dividing by or multiplying by a negative number, in this case -a, the sign will FLIP. so what do you end up with?
I do not know
We can eliminate answer choices A and D.
okay
this is just a guess is the answer a
@Jhannybean
... didn't we just say the answer choice A and D can be eliminated?
eliminated means removed, as in they do not count. As in they are not going to be one of your answer choices,
oh sorry I am a hot mess today
I am going to guess on b then
@JhannyBean
Just letting know now, all your answer choices are incorrect for this problem. None of them match up to your function.
they are let me see
Solve for x. -ax + 4b > 9 x > the quantity negative 3 times b minus 5 all over negative a x < the quantity 5 minus 3 times b all over negative a x < the quantity negative 3 times b plus 5 all over negative a x > the quantity negative 3 times b plus 5 all over negative a
is that better
\[\frac{-ax}{-a} \gt \frac{9-4b}{-a}\]\[x \lt \frac{9-4b}{-a}\] Or otherwise written as "x < the quantity of 9 minus 4 times b all over negative a"
So I guess b would work here, if that's all you're left to work with :\
may u help me with two more
Sorry, I'll tag in someone else for now. Open up another question and post your problem! More people can help :D
ok
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