The population of a certain kind of bacteria doubles in size every 3 minutes. The current number of bacteria in the population, N, is equal to the product of the initial number of bacteria, I, and 2 to the power of n, where n is the number of times the population has doubled.

Initially, 670,963 bacteria are in a petri dish. How many bacteria are in the petri dish after 6 minutes?
2,683,852
4,025,778
5,367,704
1,341,926
@Rachella
@sangya21

Question

The population of a certain kind of bacteria doubles in size every 3 minutes. The current number of bacteria in the population, N, is equal to the product of the initial number of bacteria, I, and 2 to the power of n, where n is the number of times the population has doubled.

Initially, 670,963 bacteria are in a petri dish. How many bacteria are in the petri dish after 6 minutes?
2,683,852
4,025,778
5,367,704
1,341,926
@Rachella 
@sangya21

anonymous · Answer

after 6 minutes it doubles twice 
answer is 
$$4\times  670,963$$

anonymous · Answer

i.e. if it double in three minutes, it doubles twice in 6 minutes

anonymous · Answer

total  =2*2* 670,963
as population doubles at every 3 mins