Question

xy=32 2xy^2=32
find the value of p and q
when x=2^p and y=2^q

Answer 1

@satellite73

Answer 2

\[xy=32\\
2xy^2=32\] right?

Answer 3

s

Answer 4

ok so we can solve for \(x\) and \(y\) by dividing

Answer 5

\[\frac{xy}{2xy^2}=\frac{32}{32}=1\] or
\[\frac{1}{2y}=1\]

Answer 6

that makes \(y=\frac{1}{2}\)
substitute this back in to either equation to find \(x\)

Answer 7

you good from there?

Answer 8

x = 64

Answer 9

yes

Answer 10

\[64=2^6,\frac{1}{2}=2^{-1}\]