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if the constant term in the expansion of (kx-1/x)^4 is 24, find k. Can you give the answer and show me how to solve it please?
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so when you multiply all that out you will have the constant term is 24
so I guess you know how to expand this using pascal's triangle?
if not we can straight multiply it out
\[(a+b)^4=1(a)^4+4(a)^3(b)+6(a)^2(b)^2+4(a)(b)^3+1(a)^4\]
all you really have to do is replace a with kx and b with -1/x
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then figure out what term doesn't have any x's after simplifying
and that will be your constant term
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