Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (s):

Find the volume of the solid (using washers method) obtained by rotating the region bounded by the curves x=0, y-2, y=square root of x about the y- axis.

OpenStudy (anonymous):

|dw:1417409557496:dw|

OpenStudy (jhannybean):

Is that y=2 or x=y-2?

OpenStudy (s):

y=2

OpenStudy (jhannybean):

Because it didn't look like y=2, wasnt sure.

OpenStudy (jhannybean):

Oh ok.

OpenStudy (anonymous):

I think washer is \(2\pi r h\), right?

OpenStudy (s):

sorry. I am a little confused what should r be equal to?

OpenStudy (anonymous):

In this case: \[ r = x\\ h = 2-\sqrt{x} \]

OpenStudy (s):

washers is pi r^2

OpenStudy (anonymous):

Oh, ok...

OpenStudy (anonymous):

So we're integrating with respect to \(y\) then, right?

OpenStudy (anonymous):

\[ r=x=y^2 \]

OpenStudy (s):

yes

OpenStudy (anonymous):

\[ V = \pi\int_0^2 (y^2)^2\;dy \]

OpenStudy (anonymous):

We use : \[ y=\sqrt x \implies y^2=x \]

OpenStudy (anonymous):

|dw:1417410058885:dw|

OpenStudy (s):

oh, I got my mistake! I used wrong limits! Thanks!

OpenStudy (jhannybean):

|dw:1417410213349:dw| your limits. heh.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!