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Find the volume of the solid (using washers method) obtained by rotating the region bounded by the curves x=0, y-2, y=square root of x about the y- axis.
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|dw:1417409557496:dw|
Is that y=2 or x=y-2?
y=2
Because it didn't look like y=2, wasnt sure.
Oh ok.
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I think washer is \(2\pi r h\), right?
sorry. I am a little confused what should r be equal to?
In this case: \[ r = x\\ h = 2-\sqrt{x} \]
washers is pi r^2
Oh, ok...
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So we're integrating with respect to \(y\) then, right?
\[ r=x=y^2 \]
yes
\[ V = \pi\int_0^2 (y^2)^2\;dy \]
We use : \[ y=\sqrt x \implies y^2=x \]
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|dw:1417410058885:dw|
oh, I got my mistake! I used wrong limits! Thanks!
|dw:1417410213349:dw| your limits. heh.
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