Question

Derivative of f(x)=sin(x)cos^(2) (pi-x). I got cos^(3)(pi-x)+sin^(3)(pi-x). Is that right?

Answer 1

looks right, let me check it

Answer 2

no not quite

Answer 3

lets agree that
\[\cos(\pi-x)=-\cos(x)\] to start

Answer 4

yup I got that :)

Answer 5

so what you are really looking at is
\[-\sin(x)\cos^2(x)\]

Answer 6

then i would get rid of the \(\pi-x\) not the other way around

Answer 7

in fact perhaps your answer is right, but i would not use \(\pi-x\) as the input, just us \(x\) to make life easier

Answer 8

you should get
\[-\cos^3(x)+2\cos(x)\sin^2(x)\] if i am not mistaken