Question

you must match the number and type of solutions for the following two functions in standard form.
f(x) = x2 + 6x – 16
g(x) = x2 +6x + 1
Match the following descriptions of the solutions to each of the functions above.
Hint: they each have their own match.

Two real irrationals solutions
Two real rationals solutions

Answer 1

@ganeshie8 help?

Answer 2

well you need to use the discriminant... its part of the general quadratic formula and can tell you the type of solutions you will get.

the discriminant is

\[\Delta = b^2 - 4ac\]

in your 1st question a = 1, b = 6 and c = 16

substitute the values and calculate an answer for the discriminant

then match you answer to the following conditions

\[\Delta > 0\]

you will have 2 unequal roots..

1. if the answer is a perfect square the roots are real and rational.

if the answer is not a perfect square the roots are real an irrational

\[\Delta = 0\]

you have 2 equal real and rational roots.


\[\Delta < 0\]

the quadratic has no real roots, only complex.

hope it makes sense

Answer 3

@campbell_st thank you so much!

Answer 4

oops 1st question a = 1 b = 6 and c = -16... sorry for the typo

Answer 5

it makes a huge difference to the answer

Answer 6

thank you! @campbell_st