A local company employs a varying number of employees each year, based on its needs. The labor costs for the company include a fixed cost of $30,383.00 each year, and $26,590.00 for each person employed for the year. For the next year, the company projects that labor costs will total $2,051,223.00. How many people does the company intend to employ next year?
@sammixboo
@sangya21

Question

A local company employs a varying number of employees each year, based on its needs. The labor costs for the company include a fixed cost of $30,383.00 each year, and $26,590.00 for each person employed for the year. For the next year, the company projects that labor costs will total $2,051,223.00. How many people does the company intend to employ next year?
@sammixboo 
@sangya21

anonymous · Answer

As the labor charges are fixed for every year thus
$2,051,223.00 - $30,383.00 = y
no. of employees = y  /  $26,590.00= x

anonymous · Answer

Find x and y

sammixboo · Answer

Well, we have

$\rm $30,383.00~+~$26,590.00p~=~$2,051,223.00$

We are finding the value of p, which is the people the company tend to employ next yea,

sammixboo · Answer

To solve this, we must first subtract $\rm $30,383.00$ on both sides of the equation to get p alone

$\rm $30,383.00~-~$30,383.00~+~$26,590.00p~=~$2,051,223.00~-~$30,383.00$

$\rm $26,590.00p~=~$2,051,223.00~-~$30,383.00$

Now can you tell me what is $\rm $2,051,223.00~-~$30,383.00$?

swaqqout_kid1 · Answer

2020840

sammixboo · Answer

Yes, it equals $\rm 2,020,840$, so now plug in $\rm 2,020,840$ where $\rm $2,051,223~-~$30,383$ was in the equation

$\rm 26,590p~=~ 2,020,840$

Now we must divide $\rm 26,590$ on both sides of the equation to get p alone

$\rm \frac{26,590p}{26,590}~=~ \frac{2,020,840}{26,590}$

$\rm p~=~ \frac{2,020,840}{26,590}$

Now, what is $\rm 2,020,840\div 26,590$

swaqqout_kid1 · Answer

76

sammixboo · Answer

Yes! So there would be around 76 people next year