Question

The doubling period of a bacterial population is 20 minutes. At time t = 100 minutes, the bacterial population was 80000.

What was the initial population at time t = 0 ?

Find the size of the bacterial population after 3 hours.

Answer 1

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Answer 2

can you help me with this problem?

Answer 3

yes

Answer 4

okay so every 20 mins the baceria doubles

Answer 5

0 to 20 to 40 to 60 to 80 to 100
at time 0, it was lets say k
at 20 it was 2*k
at 40 =2*2* K
at 60 =2*2*2*k
at 80 = 2*2*2*2*K
at 100=2*2*2*2*2*K, or 2^5*K or 2^(100/20) * K
we also know at 100 mins it was 80000
2^5*k=80,000
k=80,000/2^5

Answer 6

now for 300,
there are a total of 300/20 = 30/2 = 15 periods
so it will dobl 15 times
2^15*K=?
we calculated k from earlier

Answer 7

im not sure if I'm getting the 2nd part right….finding the size of bacterial population after 3 hours

Answer 8

wat did u get

Answer 9

oh oops

Answer 10

3 hours is not 15 doubling hehe

Answer 11

haha

Answer 12

3 hours = 180 mins so
180/20=18/2=9
2^9*k=?

Answer 13

are you able to help me with more? you're very helpful

Answer 14

dont worry there are lots of helpers

Answer 15

here

Answer 16

A wooden artifact from an ancient tomb contains 45 percent of the carbon-14 that is present in living trees. How long ago, to the nearest year, was the artifact made? (The half-life of carbon-14 is 5730 years.)

Answer 17

make another question someone will help you soon if its not me

Answer 18

okay so

Answer 19

Find the time required for an investment of 5000 dollars to grow to 6300 dollars at an interest rate of 7.5 percent per year, compounded quarterly.

Answer 20

how about this one?