Question

Please help me out. :)

Answer 1

#5 only. :) thank you! ^_^

Answer 2

I'd say first you would need the specific gravity of mercury which is 13.55

Answer 3

ahh.. then?

Answer 4

The cube is submerged (32/60) of the way into the mercury.
If it were the same density as mercury then it would be (60/60) of the way into the mercury. (100% submerged)
It is (32/60) (or 8/15) into the mercury.
Therefore, the density must be 8/15 of mercury's density or about 7.226
However, this is not taking into account the affect of the water surrounding it.

Answer 5

I don't understand. Sorry. :(

Answer 6

You don't understand about the water or you don't understand my entire explanation?

Answer 7

am, your entire explanation...

Answer 8

Since you asked the question, are you studying density, specific gravity, etc?

Answer 9

yes... but I don't understand it.. I'm confused. I don't know what to do..

Answer 10

So, besides the specific gravity, the teacher wants an explanation of why the specific gravity is 7.226?

Answer 11

am... no... wait... let me clear something ... is 7.226 the final answer?

Answer 12

No - I am not taking into account the buoyancy of the water acting on the cube. (I'm not exactly sure how to do that.)

Answer 13

Aww! Okay. But thanks for the help... I appreciate it.

Answer 14

Okay :-)