Mathematics
14 Online
OpenStudy (anonymous):
log (0,4^2)/20^4 =
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OpenStudy (anonymous):
OpenStudy (anonymous):
\[\log(\frac{a}{b}) = \log(a) - \log(b)\]
OpenStudy (jhannybean):
Is that really a decimal point?
OpenStudy (anonymous):
yes it is..
OpenStudy (anonymous):
, and . on keyboard are close to each other, one can do mistake in that, simple to understand it..
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OpenStudy (jhannybean):
Wth is \[\log\left(\frac{0.4^2}{20^4}\right)\]
OpenStudy (anonymous):
It is what you have written.. :P
OpenStudy (anonymous):
Not a function but a question to simplify it more..
OpenStudy (anonymous):
\[\log\left(\frac{0.4^2}{20^4}\right) = \log(0.4^2) - \log(20^4)\]
OpenStudy (anonymous):
And power rule for logs says that:
\[\log(a^m) = m \cdot \log(a)\]
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OpenStudy (jhannybean):
\[\log\left(\frac{a}{b}\right) = \log(a)-\log(b)\]\[\log\left(\frac{0.4^2}{20^4}\right) = 2\log(0.4) -4\log(20)\]
OpenStudy (anonymous):
@pain100 should we assume base as \(10\) or do you have something else in your pocket?
OpenStudy (anonymous):
First value will be negative...
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
yes is reply to what?? first question or second one?
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OpenStudy (jhannybean):
\[0.4= \frac{2}{5}\]\[\log(0.4^2) = 2\log\left(\frac{2}{5}\right)=2\cdot [\log(2)-\log(5)]\]
OpenStudy (anonymous):
@beans you are going now in depths.. :P
OpenStudy (jhannybean):
Lmao. Just playing around with the function.
OpenStudy (anonymous):
Who is this beans?? Oh my God,
OpenStudy (anonymous):
base 10
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OpenStudy (jhannybean):
\[4\log(20)=4\log(5\cdot2^2) = 4\log(5)+2\log(2)\]
OpenStudy (anonymous):
Jhanny let us make it more simple..
OpenStudy (jhannybean):
I am!!
OpenStudy (jhannybean):
\[\log\left(\frac{0.4^2}{20^4}\right) = 2\log(0.4) -4\log(20)\]\[=2\log(2)-2\log(5)+4\log(5)+2\log(2)\]
OpenStudy (anonymous):
\(log_{10}(0.4) = -0.3979\)
\(log_{10}(20) = 1.3010\)
Like this.. :P
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OpenStudy (jhannybean):
Noooo
OpenStudy (jhannybean):
I think mine is better :-)
OpenStudy (anonymous):
But finally you have to evaluate it..
OpenStudy (jhannybean):
Ik. But still!
OpenStudy (perl):
in european countries 0,4 = 0.4
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OpenStudy (jhannybean):
\[\implies 2\log(2)-2\log(5)+4\log(5)+2\log(2)\]\[=4\log(2)-2\log(5) = \log(2^4)-\log(5^2)=\frac{\log(2^4)}{\log(5^2)}\]
OpenStudy (anonymous):
Suppose you have options like : a) -6 b) -12 c) None..
I got \(-5.9999\) which is close to \(-6\).. :P
OpenStudy (jhannybean):
Hah!
OpenStudy (anonymous):
Here is.. :P
OpenStudy (anonymous):
umm my friend says the answer is -6
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OpenStudy (anonymous):
Who is your that friend?
OpenStudy (anonymous):
OpenStudy (anonymous):
is this true?
OpenStudy (jhannybean):
Oh I see where I messed up, lol.
OpenStudy (anonymous):
@Jhannybean again look at \(4 \log(20)\) evaluation you have done above..
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OpenStudy (jhannybean):
Yeah ik ik,.. I see it,lol.
OpenStudy (anonymous):
\[4 \log(20) = 4 \log(5) + 4 \log(4)\]
OpenStudy (jhannybean):
Or... \[4\log(5)+8\log(2)\]
OpenStudy (jhannybean):
\[\log_{10}\left(\frac{0.4^2}{20^4}\right) = 2\log(0.4) -4\log(20)\]\[=2\log(2)-2\log(5)-4\log(5)-8\log(2)\]\[=-6\log(2)-6\log(5)\]\[=-6\]
OpenStudy (dan815):
umm
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OpenStudy (anonymous):
Where @Jhannybean ??
No you are good everywhere. :P
OpenStudy (anonymous):
\[-6(\log(2) + \log(5))\]
OpenStudy (anonymous):
= -6 ??
OpenStudy (jhannybean):
Yes, plug it into your calculator lol
OpenStudy (anonymous):
I got -5. something.
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OpenStudy (dan815):
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