Mathematics
15 Online
OpenStudy (anonymous):
The triangle shown is a right triangle. Create the equation to be used to find the missing lengths. Do not solve the equation.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
is there an image?
OpenStudy (anonymous):
OpenStudy (anonymous):
In a right triangle, all the sides correspond to and equation called pythahrian thyreom
OpenStudy (anonymous):
this equation is a^2+b^2=c^2
OpenStudy (anonymous):
c^2 is the longest side of the triangle, or the hypothenuse
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so in this triangle what is the longest side?
OpenStudy (anonymous):
y?
OpenStudy (anonymous):
yep, so c = y
OpenStudy (anonymous):
and a and b are the remaining sides
OpenStudy (anonymous):
I need to find y though
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so plugging the rest of the numbers into the equation
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
you will get 3^2 + 3^2= y^2
OpenStudy (anonymous):
6^2?
OpenStudy (anonymous):
no because 3^2 = 9, so 9 + 9=18 6^2 = 36
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so the answer is 36.
OpenStudy (anonymous):
you could do 2(3^2)
OpenStudy (anonymous):
I dont have that option
OpenStudy (anonymous):
6^2 does not equal 3^2+3^2
OpenStudy (anonymous):
ok
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
right now we have 3^2 + 3^2=y^2
OpenStudy (anonymous):
but we need y by itself
OpenStudy (anonymous):
so take the square root of both sides
OpenStudy (anonymous):
(but don't simplify because they ask you not to
OpenStudy (anonymous):
class is almost over. can we speed this up?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
your final answer should look like y=sqrt(3^2+3^2)
or y=sqrt(2(3^2))
OpenStudy (anonymous):
\[y=\sqrt{2(3^{2})}\]
OpenStudy (anonymous):
thats the answer but the program looks a bit confusing, not sure if you can even plug that in, on paper its correct if you show your teacher