Question

the vertex of this parabola is at (2,-4). When the x-value is 3, the y-value is -1. what is the coefficient of the squared expression in the parabolas equation

Answer 1

so write like this
y=ax^2+bx+c first

Answer 2

the coefficient is then what is in front of x^2

Answer 3

so the coefficient of x^2 for this particular parabola's equation I have written is a

Answer 4

so example:
\[\text{ find coefficient of } x^2 \\ y=(3x+2)^2 \\ y=(3x)^2+2(2)(3x)+(2)^2 \\ y=9x^2+12x+4\]
The coefficient of x^2 is 9

Answer 5

And if you wanted to find the coefficent of x
you would say 12 in this case

Answer 6

and if you wanted to know the constant term it is 4 in this case

Answer 7

in general, once you have in this form
y=ax^2+bx+c then you can determine the following:
coefficient of x^2 is a
coefficient of x is b
constant term is c

Answer 8

oh I didn't see that whole question

Answer 9

I just seen how to find the coefficient of a x^2 for a parabola
sorry

Answer 10

\[y=a(x-h)^2+k \text{ where } (h,k) \text{ is the vertex}\]

Answer 11

what is h?
what is k?

Answer 12

hint: h and k are given in your problem

Answer 13

well to find a you will then use f(3)=-1 <--but do this part after pluggin in h and k

Answer 14

a will be your answer

Answer 15

when you find it

Answer 16

let me know if you come back and need my help