Question

fine the value of rel number y such that ( 3+2i)(1+iy) is (a)real and (b) imaginary

Answer 1

please you have to apply the distributive property of multiplication over addition, in order to perform your calculus

Answer 2

namely:
\[(3+2i)(1+iy)=3(1+iy)+2i(1+iy)=\]
please try

Answer 3

Please, I can not say you the solution directly, since the code of conduct

Answer 4

so, please continue the above calculus that I have wrote

Answer 5

(3-2y)+i(2y+2) now next?

Answer 6

sorry I got:
(3-2y)+i(2+3y)

Answer 7

oh yes just writng mistake but now next ?

Answer 8

ok! if you want a real number, you have to set:
2+6y=0, then solve for y;
similarly if you want an imaginary number, you have to set:
3-2y=0, and then solve for y again

Answer 9

sorry I have made an error,
...you have to set 2+3y=0...

Answer 10

thank you but why we put os equal to zero?

Answer 11

when you set 3-2y=0, your number becomes:
i(2+3y), which is an imaginary number.
SImilarly, when you set 2+3y=0, your number becomes:
3-2y, which is a real number!

Answer 12

for example in the first case you get y=3/2, and your number is:
i(2+3*3/2)=i*13/2
whereas in the second case you get y=...
please try!

Answer 13

@ziawasim