What is the solution to the system of equations x=3y+5 x-4y=3
1) x=3y +5 subtract 3y from both sides and you will get -3y-x=5 then subtract x from both sides and you will get -3y=-x+5 divide the whole equation by negative three your answer is \[y=-\frac{ 1 }{ 3 }x+5\] 2) x-4y=3 subtract x from both sides and you will get -4y=-x+3 divide the whole equation by negative four your answer is \[y=-\frac{ 1 }{ 4 }x+3\]
the answer is an ordered pair though
ohhh ok just a minute
ok
are you there
ya is it asking you to find either x or y?
both
ok so first you need to get the first equation switched around so it equals a number like the second equation x=3y+5 subtract 3y from both sides 3y+x=5 x-4y=3 (your second equation) then you need to first eliminate x by subtracting the two equations
ok so you need to subtract them
how do i do that @Sticky
\[\frac{ x-3y=5 }{ x-4y=3 }=7y=2\]
so y=7
and x=2
no \[y=\frac{ 2 }{ 7 }\]
you had to divide 7y by 7 and 2 divieded by 7 to get y
so y= 3.5
yes now substitute 3.5 as Y in one of the equations to find x
so x=22.5
x=15.5
is that right
@Sticky
I don't think so :/ I'm pretty sure I messed up somewhere you solved it right but there should only be one x just a minute
ok
@Gondola
I think its (-5.5,3.5)
how
ok thank you
bye
http://www.purplemath.com/modules/systlin5.htm if its wrong you can find out how to do it here sorry for all the trouble :/
thank you so much it help
no probs cya
Join our real-time social learning platform and learn together with your friends!