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Write the expression as a complex number in standard form. help??
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What's the expression?
2i/3-4i @rosho
2i/(3-4i)??
yes i think i cant quite type it on here right @rosho
Okay, so what you need to do is to multiply the top and bottom like this: (3+4i) 2i(3+4i)/(3-4i)(3+4i) 6i+8(i^2)/(9-16(i^2) 6i-8/(9+16)
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get it?
what @rosho did was multiply top/bottom by conjugate to get rid of imaginary number in denominator
but wouldnt my answer be like -8+6i?/-7 or 25 @rosho @dumbcow
i=sqrt(-1) i^2=-1
ohh okkay thankss ! @rosho
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NP!
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