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Calculus1 15 Online
OpenStudy (anonymous):

Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) lim x→−12 x2 + 25 − 13 x + 12

OpenStudy (anonymous):

X approaches -12 so just plug -12 for x and solve the equation

OpenStudy (anonymous):

there are no restrictions. all of your functions are polynomials. 2nd one is of degree 0, 3rd on is of degree 1, and 1st one is of degree 2. A polynomial is by definition continuous over \(\large\color{black}{ (-\infty ,+\infty) }\), and thus a limit of f(x), as x approaches any (real) number c, is going to give as the value of f(c). and thus the conditions of continuity are met:) lim{x-> c} f(x) = f(c) obviously, therefore also, lim{x->c} f(x) exists. and f(c) exists.

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