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Evaluate the limit, if it exists. (If an answer does not exist, enter DNE.) lim x→−12 x2 + 25 − 13 x + 12
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X approaches -12 so just plug -12 for x and solve the equation
there are no restrictions. all of your functions are polynomials. 2nd one is of degree 0, 3rd on is of degree 1, and 1st one is of degree 2. A polynomial is by definition continuous over \(\large\color{black}{ (-\infty ,+\infty) }\), and thus a limit of f(x), as x approaches any (real) number c, is going to give as the value of f(c). and thus the conditions of continuity are met:) lim{x-> c} f(x) = f(c) obviously, therefore also, lim{x->c} f(x) exists. and f(c) exists.
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