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The Derivative of y=x ln ^{3}x ?
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I think you've made a typo in your equation, can you have another look at it?
\[y = x \ln ^{3}x\]
Oh it was right, ignore me haha. So to do this we're going to need the product rule. If we say f(x)=x and g(x)=ln^{3}x, what is f'(x) and g'(x)?
f'(x) = 1 and g'(x) =\[3x (\ln x)^{2} \]
Not quite, very close though. d/dx(ln(x))=1/x so it should be 3ln(x)^2/x
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\[3\ln x ^{\frac{ 2 }{ x}} \] Like this??
nvm i figured out the answer.
Great :)
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