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Mathematics 16 Online
OpenStudy (anonymous):

if f(x)= cosxsin3x, then f'(pi/6) is equal to ? can't seem to figure this one out ...

OpenStudy (anonymous):

Can you differentiate f(x) using the product rule?

OpenStudy (anonymous):

well when i used the product rule i got 3cosxcos3x-sin3x(sinx) is this correct?

OpenStudy (solomonzelman):

yes.

OpenStudy (solomonzelman):

you simplified smart:)

OpenStudy (anonymous):

Looks correct to me, now sub in x=pi/6 for your answer.

OpenStudy (anonymous):

okay yes i tried that but how do i multiply the cos 3 and pi/6 ?

OpenStudy (anonymous):

All you have to do is 3*cos(pi/6)*cos(3pi/6)-sin(3*pi/6)sin(pi/6) Simplifying the fractions we're left with: 3*cos(pi/6)*cos(pi/2)-sin(pi/2)sin(pi/6)

OpenStudy (anonymous):

okay so the answer is -1/2?

OpenStudy (anonymous):

okay. thank you so much ! :)

OpenStudy (solomonzelman):

Anytime, I only verified it.

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