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if f(x)= cosxsin3x, then f'(pi/6) is equal to ? can't seem to figure this one out ...
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Can you differentiate f(x) using the product rule?
well when i used the product rule i got 3cosxcos3x-sin3x(sinx) is this correct?
yes.
you simplified smart:)
Looks correct to me, now sub in x=pi/6 for your answer.
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okay yes i tried that but how do i multiply the cos 3 and pi/6 ?
All you have to do is 3*cos(pi/6)*cos(3pi/6)-sin(3*pi/6)sin(pi/6) Simplifying the fractions we're left with: 3*cos(pi/6)*cos(pi/2)-sin(pi/2)sin(pi/6)
okay so the answer is -1/2?
yes, it is -1/2. http://www.wolframalpha.com/input/?i=+3cos%28pi%2F6%29cos%28pi%2F2%29-sin%28pi%2F2%29%28sin%28pi%2F6%29%29
okay. thank you so much ! :)
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Anytime, I only verified it.
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