Question

a car turns a corner going 8m/s. The corner has 30 meters.
A.find the centripetal acceleration of the car
B. If the car is 1200kg find the centripetal force necessary to turn the corner
C.what gives the centripetal force to the car?

Answer 1

Have you drawn a free body diagram yet?

Answer 2

nope

Answer 3

Do you know what that is?

Answer 4

nope

Answer 5

Well, after you draw a free body diagram or find all the forces you will then combined two equations \[\sum_{?}^{?}F=ma _{r} \] and \[a _{r}=m(v ^{2}/r) \]

Answer 6

Have you seen either of those equations?

Answer 7

Would you like me to help you with a free body diagram as well?

Answer 8

yes i had

Answer 9

yes please

Answer 10

okay.

Answer 11

Those will be your sum of the forces or \[\sum_{}^{}F \]

Answer 12

do you need help?

Answer 13

what does this mean, the corner is 30 meters

Answer 14

I suppose that is the radius

Answer 15

That's what I took it as, but I read it quickly. I notice why you are asking now.

Answer 16

I think she might be working the problem out now since she was responding right away.

Answer 17

@rachelsmith0
Please check ( will delete after you check)
for the first one i got
a) a = v^2/r = 8^2/30

b) F = m*v^2/r
= 1200 * 8^2 / 30

c) the friction from the road supplies the force to turn the car

Answer 18

@rachelmsmith0

Answer 19

yes those were all of my thoughts exactly

Answer 20

if 30 is radius... if 30 is radius I can't quite figure out how to change meters into radius.

Answer 21

what do you mean change meters into radius