Question

find F'(x)
when f(x)=e^-(lnx)

Answer 1

@satellite73

Answer 2

@Callisto

Answer 3

derivative(e^x) = e^x
except just multiply by the derivative of what it's raised to for more than just x

Answer 4

e^-(lnx)=e^(ln 1/x)=1/x
derivative of 1/x=-1/x^2.

Answer 5

hmmm
\[-\ln(x)=\ln(\frac{1}{x})\]

Answer 6

@tom982 it is 1/x

Answer 7

e.g., y = e^2x
y' = 2e^2x

Answer 8

and \[e^{\ln(\frac{1}{x})}=\frac{1}{x}\]

Answer 9

@Princer_Jones has it.

Answer 10

And instead of writing `F'(x)` you should have f'(x). F(x) can mean something totally different.

Answer 11

@satellite73 I did solve and answer is -x^(-2) but it is worn g

Answer 12

@Jhannybean , oh sorry but I mean f'(x)

Answer 13

any thought plz

Answer 14

@HASSAN(x) i already solved it. do check. and @satellite73 also gave the idea

Answer 15

Follow how @Princer_Jones solved it in his post, then compare your work.