find tan(theta) and cot(theta) if sec(theta) is 4 and sin (theta) is less than 0
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there is a picture of an angle whose secant is \(4\) you need the other side which you find via pyathagoras then you can take all the trig ratios you like
do you know another way? we're using reciprocal identities, quotient identites and pythagorean identities.
it is the same thing it all amounts to finding the third side as \[\sqrt{4^2-1^2}=\sqrt{15}\]
sorry if did not come back im helping some one else
you have \[\sec(\theta)=4\] so right way you know \[\cos(\theta)=\frac{1}{4}\]
to find the other two you need \(\sin(\theta)\) which we get from the triangle as \[\sin(\theta)=-\frac{\sqrt{15}}{4}\] but you can use an identity if you like
\[\sin(\theta)=\pm\sqrt{1-\cos^2(\theta)}\] if you compute \[-\sqrt{1-\left(\frac{1}{4}\right)^2}\] you still get \[-\frac{\sqrt{15}}{4}\] it just takes longer
so would i use the quotient identity cot(theta)= cos(theta)/sin(theta)?
yes but it is silly
the denominators will cancel, might as well go right to the answer you know from the triangle
this is the way my teacher is teaching it. first day today on this topic lol
you get from the triangle everything just make sure you know if it is positive or negative \[\cot(\theta)=-\frac{1}{\sqrt{15}}\] for example
i sort of get it now. still trying how to find tan(theta)
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