Question

how to find particular solution of differential equation. y=23/x; y=16 when x=1

Answer 1

Do you mean \(y'=\dfrac{23}{x}\) ?

Answer 2

yes!

Answer 3

You're given a separable equation. Split the differentials:
\[\frac{dy}{dx}=\frac{23}{x}~~\iff~~dy=\frac{23}{x}~dx\]
Then integrate both sides.

Answer 4

can you write it out for me please?

Answer 5

\[\int dy=\int\frac{23}{x}~dx\]

Answer 6

nxt steps?

Answer 7

\[\frac{d}{dx} \ln(x) = \frac{1}{x} \iff \int \frac{1}{x} dx =~?\]

Answer 8

lnx+c

whats next?