Question

medals!!!!
solve 5+√x+2=8+√x-7

Answer 1

@ganeshie8

Answer 2

\[5+\sqrt{x+2} =8+\sqrt{x-7}\]Square both sides \[(5+\sqrt{x+2})^2=(8+\sqrt{x-7})^2\] what do you get ?

Answer 3

13√x+3^2 so 13 √9

Answer 4

Hmm, let me check. \[(5+\sqrt{x+2})^2=(8+\sqrt{x-7})^2\]\[\implies 25 +10\sqrt{x+2}+x+2=64 +16\sqrt{x-7} +x-7\]This is what I got thus far.

Answer 5

Simplifies to \[27 +10\sqrt{x+2} = 57+16\sqrt{x-7}\]

Answer 6

so whats the final answer?

Answer 7

27+10√x+2?

Answer 8

Wait, is it \(\sqrt{x}\) or \(\sqrt{x+2}\)?

Answer 9

If it's he first then we're doing it wrong.

Answer 10

its the second

Answer 11

Okay. I think there may be an easier method in solving this. One moment.

Answer 12

I think you'd want to get rid of the \(5\) or the \(8\) first.

Answer 13

You have \[5+\sqrt{x+2}=8+\sqrt{x-7}\]You can isolate one of the radicals.\[\sqrt{x+2} = 3+\sqrt{x-7}\]NOW you square both sides. what we did at first made it a little bit more confusing. \[x+2 = (3+\sqrt{x-7})^2\]\[x+2 = 9+6\sqrt{x-7}+x-7\]Move everything over to the left hand side

Answer 14

Move everything over and simplify. \[-6\sqrt{x-7}=0\]divide both sides by -6\[\sqrt{x-7}=0\]square both sides \[x-7=0\]Add -7 to both sides and you get?

Answer 15

Let me know if there is a sep you do not understand.

Answer 16

step*

Answer 17

yea that will be great

Answer 18

Anything confusing?

Answer 19

I practically gave you the answer, all you have to do is solve for x by adding +7 to both sides and you're asking me for the answer?

Answer 20

x+9?

Answer 21

then 9√6

Answer 22

Go back up to my post where I break down the problem step by step and you will find yoru x value.

Answer 23

I do not know where you are getting these numbers.