Question

The system of equations is coincident.
What are the missing values?
-2x + 5y = -12
-6x + _ y = _

Answer 1

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Answer 2

I'm guessing the underscores are whats missing?

Answer 3

yup

Answer 4

Well, int the second one, the y is missing so you have to solve for x in the first then put them together to solve for the y and get the solution in the second if I'm not mistaken.

Answer 5

Do you know how to solve for x?

Answer 6

@Secret-Ninja there is not enough details to solve for x..

Answer 7

It is given that : the lines are coincident... we must use that..

Answer 8

Well, I know that, but to set it up so that is is on its own side is what I meant.

Answer 9

well that's all of the question

Answer 10

For two equations like :
\(a_1x + b_1y = c_1\)
\(a_2x + b_2y = c_2\)
If lines are coincident, then:
\[\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}\]

Answer 11

it has to be solved by putting in the rest of the equation that makes it coincident
you have to put it in standard form

Answer 12

So:
\[\frac{-2}{-6} = \frac{5}{b_2} = \frac{-12}{c_2}\]

Answer 13

there are two equations you just have to finish one

Answer 14

From here, solve for \(b_2\) and \(c_2\)..

Answer 15

-2x + 5y = -12
move the 5y
-2x = -12 - 5y (subtracted because it changes when flipped)
now you divide the -2 and x
so you get:

\[x = \frac{ 5y }{ 2 } + 6\]

Answer 16

so its 5y=-2x+6?

Answer 17

Second equation must be a multiple of first..

Answer 18

As you can see, second equation is 3 times first, by looking at \(x\) coefficient.. So, multiply every coefficient of first equation with \(3\), you will get what you require here.

Answer 19

-2x + 5y = -12
-6x + _ y = _
---------------
If the lines are to be coincident, then they will coincide, be the same line.
So, the equations have to be equivalent.

Looking at the x terms, 3 times -2x = -6x

So, multiply 3 times 5 to get 15 for the missing coefficient of y.

Multiply -12 by 3 to get the missing constant term.

@help-_-please