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with whay
f(t) = ((t-1)/t^2+1)) and g(t) = ((t+3)/(t+4))
need to find (f o g)(t)
t equals 1
sorry but i cant do this ps maby luckycoins888 can
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just need to simplify the expression
no i ment @luckycoins888 can
@wio
who is @wio?
basically have to simplify ... \[(((t+3)/(t+4))-1)/((t+3/(t+4))^2 + 1\]
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@Jhannybean
t = 1
not trying to solve for t
Wow, this one is hard...
\[ (f\circ g)(t) = \frac{g(t)-1}{[g(t)]^2+1} \]
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Start with the top: \[ g(t)-1 = \frac{t+3}{t+4}-1 = \frac{t+3}{t+4}-\frac{t+4}{t+4} \]
|dw:1417553672996:dw|
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