Question

@Michele_Laino

Answer 1

your trying?

Answer 2

yup, both side

Answer 3

@phi

Answer 4

close:
\[ \frac{d}{dx}y^3 = 3y^2 \frac{dy}{dx} \]

Answer 5

ohh

Answer 6

on the other hand
\[ \frac{d}{dx}x^3 = 3x^2 \frac{dx}{dx} = 3x^2 \]

Answer 7

ohh i got it

Answer 8

now what do i do ?

Answer 9

the left side

Answer 10

let me use d instead of d/dx (easier to type):
d(4-xy) = d (4) - d(xy)
what is the derivative of a constant 4 with respect to x ?
for the 2nd term d(xy) use the product rule.

Answer 11

idk nvm im gonna skip it

Answer 12

the derivative of a constant is one of the first things you learn, right ?

Answer 13

see http://www.mathsisfun.com/calculus/derivatives-rules.html

Answer 14

you are doing a problem in "implicit differentiation" You don't study that until you know how to take the derivative of constants, the power rule (which you seem to know), trig functions, and various rules: product rule, chain rule. If those do not sound familiar then you need to come up to speed before tackling this problem.

Answer 15

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