Question

CAN SOMEONE ON HERE PLEASE HELP ME?!MEDAL!!!

Answer 1

please wourk with me step by step

Answer 2

@SolomonZelman please help

Answer 3

Sure, step by step it is. :)

Answer 4

First, what is the equation for the volume of a cylinder?
Do you know?

Answer 5

pir^2h @Miracrown

Answer 6

im in such a rush :(((

Answer 7

Yep, so this one calls for differentials. We take the derivative of each term, with regard to each variable (product rule)

Answer 8

@myininaya

Answer 9

V = πr²h = 10πr²
dV/dr = 20πr
dV = 20πr dr
Let dV and dr represent the change (or error) in volume and radius. In this case, dr = ±0.1 inch, r = 4 inches, and we are asked for dV, the resulting possible error in the cylinder's volume.
dV = 20πr dr
dV = 20π(4) ±0.1
dV = ±8π inches³

Answer 10

@mondona - Rushing with your work will get you nowhere.

Answer 11

We take the derivative of each term, with regard to each variable (product rule)
and multiply by a delta for that variable
V -> delta V
r^2 -> 2 r delta r
It sounds like there is no error in the length so we can set delta L = 0
we don't know r so we can plug in ...

Answer 12

@dtan5457 - Please refrain from giving *direct answers*, it hinders the learning process.

Answer 13

Sorry, I actually have to go. If you look at my work and truly want to learn it, I'm sure you will get it. And yes, that is the answer.