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Let f:R-->R be a bounded function. Prove that f is continuous if and only if the graph of f is a closed subset of R^2. What if f is unbounded? Please, help
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@Miracrown
It's advance calculus part compact sets
Why don't we start with the first direction.
We will assume that \(f\) is continuous and we want to show that the graph of \(f\) is closed in \(\mathbb{R}^2\).
To show that it is closed we will prove that the complement of the graph is open.
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We will consider an arbitrary point in the complement and show that we can find a ball around the point contained in the complement.
Show me more, please. I have no clue. :)
Do you understand where I'm going with this so far?
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