how do i start this problem? if f(x)=x^2+sinx, show that there must be a number c such that f(c)=50 help please
is it f(c) = 50 OR is it f ' (c) = 50 ... notice the prime notation ??
f(c)=50
so it sounds like you need to solve f(x)=x^2+sinx f(c)=c^2+sin(c) 50 = c^2 + sin(c) 0 = c^2 + sin(c) - 50 you can't do this analytically, but you can get an approximation with a graphing calculator
you don't need to actually solve for c though you just need to show that such a value of c exists to make 0 = c^2 + sin(c) - 50 true
so that means you can use the intermediate value theorem do you know what I'm referring to?
don't you need interval values to use ivt?
yeah so you'll have to use a graphing calculator to spot the left and right boundaries of the interval
i see im going to use geogebra be right back
Use this if you don't have a graphing calculator https://www.desmos.com/calculator
geogebra works too (actually works better)
use x instead of c when it comes to graphing so graph x^2+sin(x)-50
ok
it must be from -7 to 7 i think
you should see 2 x-intercepts
what's a good interval for the x-intercept on the left
yeah one at -7 and the other at 7
on the left at -7
it's close to -7, but not at -7
the left x-intercept is between -8 and -7
i see
so if g(x) = x^2+sin(x)-50 then calculate g(-8) and g(-7) you should see a sign change
the sign change will indicate there is at least one root for g(x) somewhere between -8 and -7
ok
the other root is pretty close to +7, but not quite fully at +7 it's between +7 and +8 calculate g(7) and g(8) and you should see a sign change
g(-8) is about 13.01 and g(-7) -1.66
good and good
the sign change from + to - indicates we have at least one root in between there
assuming g(x) is continuous (which it is)
g(7) is -0.34 and g(8) is 14.99
very good
so this shows that there are at least 2 values of c that make f(c)=50 true we have the graph to definitively say exactly 2, but you would use the mean value theorem to prove that (which would not involve the graph at all)
ok
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