Question

How do I do this?
2y^1/3∙ 6y^1/3

Answer 1

add the exponents

Answer 2

\[\large 2y^{1/3} \times 6y^{1/3}\]

Answer 3

also \(2\times 6=12\) so
\[12y^{\frac{1}{3}+\frac{1}{3}}\]

Answer 4

So I would have
\[12y ^{2/3}\]

Answer 5

yes