Question

Identify the oblique asymptote of f(x) = quantity x squared minus 4 x plus 8 over quantity x plus 2.

y = 0
y = x - 2 <------ MY ANSWER
y = x - 6
No oblique asymptote

Can you please check this for me? @jim_thompson5910

Answer 1

oh here we go with the "overs" again

Answer 2

LOL you're funny! xD

Answer 3

\[\frac{x^2-4x+6}{x+2}\]

Answer 4

is that the right thing?

Answer 5

if so unfortunately your answer is wrong

Answer 6

+8 instead of +6 for the numerator

Answer 7

still wrong

Answer 8

oh :/ ughhhh

Answer 9

\[\frac{x^2-4x+8}{x+2}\] you know how to do synthetic division? it is real easy here

Answer 10

no

Answer 11

damn
you know polynomial long division?

Answer 12

no lol i'm STOOOOOPID! if you haven't noticed by now

Answer 13

lol stoopid is as stoopid does
you know wolfram alpha?

Answer 14

http://www.wolframalpha.com/input/?i=%28x^2-4x%2B6%29%2F%28x%2B2%29
you gotta divide
when you divide you get a quotient and a remainder
ignore the remainder, the quotation is the slant asymptote

Answer 15

there is no way to do this without doing the division
\[\frac{x^2-4x+8}{x+2}=x-6+\frac{18}{x+2}\]

Answer 16

the slant asymptote is \(y=x-6\)

Answer 17

thank you senor!! :P

Answer 18

de nada madam