Question

state the Domain and range~
k(x)=4x+3/x^2-1

Answer 1

Domain= \[\left\{ x:x \mathbb{R}-1\le x \le1 \right\}\]
I'm not sure about range...
@mathmath333

Answer 2

the degree is different on numerator and denominator so

it will be
\(\large\tt \begin{align} \color{black }{k(x)\in \mathbb{R}

}\end{align}\)

Answer 3

This will be like the other one... The uhm....
\[a^{3}-b^{3}=(a-b)(a^{2}+ab+b^{2})\]?

Answer 4

yes so the domain will be
\(\Large x\neq 1\\
\Large x\neq -1\)

Answer 5

and its
\(\Large x^2-1=(x+1)(x-1)\)

Answer 6

its not the power \(\Large 3\)

Answer 7

So I would write that, but with the K(x)ER in front?

Answer 8

it depends how ur teacher taught u

Answer 9

I don't think it matters.
So it can be written\[k(x)\in \mathbb{R} x^{2}-1(x+1)(x-1)\]?
Or without the x^2-1 in the front?

Answer 10

idk
i would write it as

domain=
\(\large\tt \begin{align} \color{black}{\{x:x\in \mathbb{R} :x\neq 1 \land
x\neq-1}\}\end{align}\)

Answer 11

Can yhu show me the steps to find the range? I couldn't get that one. ;c

Answer 12

find the domain of inverse of function
their domain will be the range