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Mathematics 10 Online
OpenStudy (anonymous):

Find the inverse and state if the inverse is a function.

OpenStudy (anonymous):

\[\large f(x) = \sqrt[3]{x} − 3 \]

OpenStudy (anonymous):

solve \[\large x=\sqrt[3]{y}-3\] for \(y\)

OpenStudy (anonymous):

takes only two steps 1) add 3 2) cube

OpenStudy (anonymous):

\[x^{3}+27 = y?\]

OpenStudy (anonymous):

oh no

OpenStudy (anonymous):

\[(x+3)^3\neq x^3+27\]

OpenStudy (anonymous):

\[x=\sqrt[3]{y}-3\\ x+3=\sqrt[3]{y}\\ (x+3)^3=y\] so \[f^{-1}(x)=(x+3)^3\]

OpenStudy (anonymous):

Ohhhh okay

OpenStudy (anonymous):

how you been, haven't seen you in a while?

OpenStudy (anonymous):

I've been good. I had a baby back in August so I've been busy with her and my other baby. But I'm relearning stuff before I go back to school next year.

OpenStudy (anonymous):

boy or girl?

OpenStudy (anonymous):

oh , her, doh

OpenStudy (anonymous):

good luck!

OpenStudy (anonymous):

Hahaa thanks. Yeah my first was a boy my second was a girl. One more question. How do I know if it's a function?

OpenStudy (anonymous):

it is a function because , well because it is \[g(x)=(x+3)^3\] is a function, put in a number, get out a number you would know it was NOT a function if you had say a \(\pm\) in it like if you solve \[x=y^2\] for \(y\) you would have to say \[y=\pm\sqrt{x}\] and that is NOT a function

OpenStudy (anonymous):

Oh yeah! Sorry it's been a while in this class.

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