Question

Did I get this right?

Answer 1

So is this how you did it?
\[\begin{bmatrix}
1& -1& 0\\
7& 0& -6\\
0& 7& 4\\
\end{bmatrix}
\times
\begin{bmatrix}
x\\
y\\
z\\
\end{bmatrix}=
\begin{bmatrix}
1\\
21\\
14\\
\end{bmatrix} \]?

Answer 2

Yeah

Answer 3

but since z=0, I was wondering if that meant it was considered that Z could be any number

Answer 4

When I do it in my calculator, I get infinite solutions

Answer 5

What are infinite solutions?

Answer 6

Which means there can be any number, since there is not enough data to find the exact solutions

Answer 7

I found the reduced row echelon form, are you using a TI-84 calculator?

Answer 8

Your answer is correct the first one. I can explain it if you want?