Question

WILL MEDAL. what is the radius of the circle given by the following equation. x^2/10+(y-2)^2/10=1
a) 30
b) sqrt10
c) 5
d) 1

Answer 1

\[\frac{x^2}{10}+\frac{(y-2)^2}{10}=1\\
x^2+(y-2)^2=10\] now you can read off the answer

Answer 2

general form is \[(x-h)^2+(y-k)^2=r^2\] for a circle with center \((h,k)\) and radius \(r\)
you have \[x^2+(y-2)^2=10\]

Answer 3

so the answer would be b? @satellite73

Answer 4

yes