I need help with a few probability questions..Please help. Pictures included.
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OpenStudy (anonymous):
OpenStudy (anonymous):
you got 9 bills total right?
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Wait no
OpenStudy (anonymous):
probability you get a $5 is
\[\frac{4}{9}\] then that bill is gone and you have 8 left
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OpenStudy (anonymous):
probability you get a $10 is \(\frac{4}{8}=\frac{1}{4}\)
OpenStudy (anonymous):
I have 43 bills. The three 1s, the four 5s, the two 10s.
OpenStudy (anonymous):
multiply those numbers get
\[\frac{4}{9}\times \frac{1}{4}=\frac{1}{9}\]
OpenStudy (anonymous):
lol you have maybe $43 but you have only 9 bills
OpenStudy (anonymous):
OHHHH. I understand what you mean now. Yeah, I get it now. I have nine bills
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OpenStudy (anonymous):
ok so you want to start again or is the answer clear?
OpenStudy (anonymous):
I think it's clear
OpenStudy (anonymous):
Yes, it is. Thank you very much. Would you possibly help me with some more similar questions? :)
OpenStudy (anonymous):
sure if i can
OpenStudy (anonymous):
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OpenStudy (anonymous):
how many letters?
OpenStudy (anonymous):
11
OpenStudy (anonymous):
k good
how many consonants
OpenStudy (anonymous):
Ummm..5?
OpenStudy (anonymous):
i count 7
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OpenStudy (anonymous):
Oh, I recounted. Seven it is.
OpenStudy (anonymous):
so first one is a consonant, \[\frac{7}{11}\] now there are 10 letters left, and 3 E's so
\[\frac{3}{10}\] multiply get
\[\frac{7}{11}\times \frac{3}{10}\]