Can someone please help me simplify this problem? (5x^3y)^2(-2x^5y^1)
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OpenStudy (jhannybean):
\[(5x^{3y})^2\cdot (-2x^{5y})\] Is this it?
OpenStudy (jhannybean):
Or is it: \((5x^3y)^2\cdot (-2x^5y^1)\)
OpenStudy (anonymous):
It's the bottom one! :)
OpenStudy (anonymous):
Second one
OpenStudy (anonymous):
@Jhannybean
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OpenStudy (jhannybean):
First, distribute the square to both variables in your first function.\[(5)^2(x^3)^2(y)^2 \cdot (-2x^5y^1)\]
OpenStudy (jhannybean):
What do you get on the left side?
OpenStudy (anonymous):
25x^9y^2?
OpenStudy (anonymous):
\[25x ^{9}-y ^{2}?\]
OpenStudy (anonymous):
Sorry positive y
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OpenStudy (anonymous):
@Jhannybean
OpenStudy (jhannybean):
Almost. Try again. \((x^3)^2 = x^{3\cdot 2}\)
OpenStudy (anonymous):
x\[x^6?\]
OpenStudy (anonymous):
@Jhannybean
OpenStudy (anonymous):
\[25x ^{6}+y ^{2}\]
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OpenStudy (anonymous):
?
OpenStudy (jhannybean):
Yes :) So you get. \(25x^6y^2 \cdot (-2x^5y^1)\) Now the next step.
OpenStudy (anonymous):
:-/ :(
OpenStudy (anonymous):
Oh umm think i got it!
OpenStudy (anonymous):
=D
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OpenStudy (jhannybean):
Stay with me here. Now we have to group our like-terms.
OpenStudy (anonymous):
Would u multiply?
OpenStudy (anonymous):
=D
OpenStudy (jhannybean):
\[(25 \cdot (-2))(x^6\cdot x^5)(y^2\cdot y^1)\]\[=-50x^{6+5}y^{2+1}\]
Simplify the powers and you're done!
OpenStudy (anonymous):
So It'd be -50x^11+ y^3 ?
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OpenStudy (jhannybean):
Yes :)
OpenStudy (anonymous):
Omg!!!
OpenStudy (jhannybean):
Wait, no.
OpenStudy (jhannybean):
there is no addition involved here, all the variables are simply being multiplied.
OpenStudy (anonymous):
Huh?
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OpenStudy (anonymous):
:(
OpenStudy (jhannybean):
hollandlife Best Response Medals 0
So It'd be -50x^11+ y^3 ?
2 minutes ago
There is no addition beween x^11 and y^3.
It is simply -50x^11y^3
OpenStudy (jhannybean):
The only things that were added were the exponents, and that is because you had two like terms (i.e to x's) multiplying eachother with different powers.