If the probability of success during the 4th event of a geometric experiment is 0.0384, which of these could be the probability of success during the 5th event of the geometric experiment?

Question

perl · Answer

Which of these?

anonymous · Answer

A.0.01536
B.0.24
C.0.6
D0.096

perl · Answer

Let p = probability of success 
Let q = 1 - p be the probability of failure. Then the probability of having the first success on the kth attempt, for k >= 1, is given by
P(X = k) = q^(k - 1) * p

perl · Answer

probability of success during 4th event of a geometric experiment is 0.0384, which of these could be the probability of success during the 5th event of the geometric experiment?

I get 
P( X=4) = q^(4-1) * p = .0384

perl · Answer

I think you can use the fact that since q and p are less than 1 , then the probability will get smaller on the next try

perl · Answer

q^3 * p = .0384

P(x=5) = q^4 * p , which must be smaller

anonymous · Answer

Yeah I thought so but thank you I understand much better.

anonymous · Answer

Thanks I got the answer it was A.