i need help with this math question let f(x) = x+4/x+1, x is not equal -1, and g (x)=x-2/x-4, x is not equal to 4. find the set of values of x such that f(x) is equal to or less than G(x)
so it is asking you to solve f(x)<=G(x)
but I don't think G(x) has been given... Is g(x)=G(x)?
or is there another type of relationship between g and G
g(x)is the same as G(x) sory just a typo
so you need to solve f(x)<=g(x)
that is \[\frac{x+4}{x+1} \le \frac{x-2}{x-4}\]
First step: Make one side of the inequality 0 by moving one fraction to the other side by either addition/subtraction which ever one works in this case
alright and second step
combine the fractions
find the zeros of the fraction and where the fraction doesn't exist
draw a number line and test the intervals around each of those numbers
so first what do you get as the inequality after the first step
im stuck on that
\[f(x) \le g(x) \\ \text{ subtract } g(x) \text{ on both sides } f(x) -g(x) \le 0\]
now combine those fractions
2/-3
him you seem to be missing the variables...
you have \[\frac{x+4}{x+1}-\frac{x-2}{x-4} \le 0\]
try combining the fractions on the left
is it x-14/(x-4)(x+1)
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