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Mathematics 7 Online
OpenStudy (anonymous):

I give Medals and Become a FAN!! Did I solve this Logarithm Corectly???

OpenStudy (anonymous):

\[\log_{4}(x+1)=3~~I~said~that~x=63 \]

OpenStudy (anonymous):

\[4^3=x+1\] you are correct.

OpenStudy (anonymous):

Oh ok and what about this one

OpenStudy (anonymous):

\[3\log_{a}7+6\log_{a}2 = 9\log_{a}14 \]

OpenStudy (anonymous):

\[2^{5+3x}=1/16\] How would I solve this one?^^

OpenStudy (anonymous):

\[3\log_{a} 7+6\log_{a} 2=9\log_{a} 14\] \[\log_{a} 7^3+\log_{a} 2^6=\log_{a} 14^9\] \[\log_{a} 7^3*2^6=\log_{a} (14)^9\] ?

OpenStudy (anonymous):

Oh ok

OpenStudy (anonymous):

\[2^{5+3x}=\frac{ 1 }{ 16 }\] \[2^5*2^{3x}=\frac{ 1 }{ 16 },2^{5x}=\frac{ 1 }{2^5* 2^4 }=2^{-9}\] 5x=? x=?

OpenStudy (anonymous):

I'll come back to this problem Later,

OpenStudy (anonymous):

correction \[2^{3x}=2^{-9},3x=-9,x=?\]

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