Question

I give Medals and Become a FAN!!
Did I solve this Logarithm Corectly???

Answer 1

\[\log_{4}(x+1)=3~~I~said~that~x=63 \]

Answer 2

\[4^3=x+1\]
you are correct.

Answer 3

Oh ok and what about this one

Answer 4

\[3\log_{a}7+6\log_{a}2 = 9\log_{a}14 \]

Answer 5

\[2^{5+3x}=1/16\]

How would I solve this one?^^

Answer 6

\[3\log_{a} 7+6\log_{a} 2=9\log_{a} 14\]
\[\log_{a} 7^3+\log_{a} 2^6=\log_{a} 14^9\]
\[\log_{a} 7^3*2^6=\log_{a} (14)^9\]
?

Answer 7

Oh ok

Answer 8

\[2^{5+3x}=\frac{ 1 }{ 16 }\]
\[2^5*2^{3x}=\frac{ 1 }{ 16 },2^{5x}=\frac{ 1 }{2^5* 2^4 }=2^{-9}\]
5x=?
x=?

Answer 9

I'll come back to this problem Later,

Answer 10

correction
\[2^{3x}=2^{-9},3x=-9,x=?\]