Question

Help please, I'm very confused

Answer 1

\[8^2+10^2=h^2\] is a start

Answer 2

square and add, what do you get?

Answer 3

it would be 64 + 100 giving me 164 = h^2

Answer 4

right?

Answer 5

yes

Answer 6

ok

Answer 7

not done yet though

Answer 8

okay how do I continue from there?

Answer 9

we got
\[h^2=164\] next we get
\[h=\sqrt{164}\]right?

Answer 10

still not done

Answer 11

okay

Answer 12

do you know how to write \[\sqrt{164}\] in simplest radical form?

Answer 13

no. Could you show me?

Answer 14

is it clear that 4 divides 164 evenly?

Answer 15

okay, it would leave me with 41

Answer 16

so we have
\[164=4\times 41\] which makes
\[\sqrt{164}=\sqrt{4\times 41}=\sqrt4\sqrt{41}\] and since \(\sqrt4=2\) final answer is
\[2\sqrt{41}\]

Answer 17

oh, do you mind explaining how you got that, so I can use it for future refernces

Answer 18

that is why you have a little box on the outside as well as a little box on the inside to fill in in your answer

Answer 19

sure lets do another by example

Answer 20

okay

Answer 21

suppose i have
\[\sqrt{50}\]
i see that \(50=25\times 2\) so
\[\sqrt{50}=\sqrt{25\times 2}=\sqrt{25}\sqrt2=5\sqrt2\]

Answer 22

the middle steps can be mental steps, just writing what i am thinking
look for a perfect square that divides the radicand evenly

Answer 23

so you would divide 25 and 2 until they are in their simpelist forms?

Answer 24

and since 2 is already the simpilist form there is you leave it as a two

Answer 25

i am actually factoring, not dividing

Answer 26

but yes you have the general idea

Answer 27

okay

Answer 28

\[\sqrt{32}=\sqrt{16\times 2}=\sqrt{16}\sqrt2=4\sqrt2\]

Answer 29

thank you for your help

Answer 30

yw