Question

in which quadrant does this solution fall y=x-1 and 2x-y=2
@SolomonZelman

Answer 1

sorry wrong one hold up

Answer 2

sure...

Answer 3

y=x-1 and -3x-5

Answer 4

\(\Large\color{black}{y=x-1 }\) and \(\Large\color{black}{y=-3x-5 }\)
right?

Answer 5

yes quadrant 3 right

Answer 6

a solution is a point in which the 2 equation intersect.
In other words, a value for x and y that makes both of the equations be true.

Answer 7

So, lets solve the equations.
I would do substitution.

Answer 8

ok

Answer 9

You are given that y is equal to \(\Large\color{black}{x-1 }\) and at the same time the y is also equal to \(\Large\color{black}{-3x-5 }\).

this way, we can say that \(\Large\color{black}{x-1=-3x-5 }\) .

just like saying, if
a=b, and a=c, THEN b=c.

Answer 10

so it is quadrant 3 because thats where the points intersect

Answer 11

no.

Answer 12

can yo solve for x, when we have
\(\Large\color{black}{x-1=-3x-5 }\) ? and do you know how we arrive at this?

Answer 13

it isnt really thats what I am getting according to my graphing calculator

Answer 14

I don't know what you are getting according to your graphing calculator, but you are supposed to solve the equation and prove it without using a graphing calculator. and this is where I am trying to get.

Answer 15

so do you understand everything so far, up to \(\Large\color{black}{x-1=-3x-5 }\) ?

Answer 16

ok and yes

Answer 17

without using a graphing calculator I am still getting quadrent 3

Answer 18

now,
\(\Large\color{black}{x-1=-3x-5 }\)
\(\Large\color{black}{x-1\color{blue}{ +1 }=-3x-5 \color{blue}{ +1 }}\)
\(\Large\color{black}{x=-3x-4}\)
\(\Large\color{black}{x\color{blue}{ +3x }=-3x-4\color{blue}{ +3x }}\)
\(\Large\color{black}{4x=-4}\)

Answer 19

Find x.

Answer 20

After finding x, find the y....

Answer 21

I have the answrt and madre a 100

Answer 22

cool....

Answer 23

yep