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Mathematics 11 Online
OpenStudy (anonymous):

Another one about verifying the identity! Please help

OpenStudy (anonymous):

OpenStudy (anonymous):

@dtuniyants you were very helpful, I'd appreciate it if you could help me with one more!

OpenStudy (anonymous):

of course, just a sec, I nedd to solve it

OpenStudy (anonymous):

When simplified it looks like this: \[1/(\tan(x-\pi/2))=-\tan(x)\]

OpenStudy (anonymous):

the absolute values of -tan(x) and tan(x-pi/2) have to be equal 1.

OpenStudy (anonymous):

How did you go about changing cot to tan? :/

OpenStudy (anonymous):

|tan(x)| can only be equal 1, when x=pi/4, 3pi/4, 5pi/4, and 7pi/4. All of these can be answers to the equation. Since there are no restrictions in range of function cot(x), all of these can be answers

OpenStudy (anonymous):

cot=1/tanx

OpenStudy (anonymous):

|dw:1417638260413:dw| Since every quadrant the sign of tan(x) changes they all are answers to the equation

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