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OpenStudy (darkbluechocobo):
On a computer network of 25,000 computers, one computer spreads a vicious virus. The total number of computers on the network that contract the virus after t hours is modeled by P(t)=25000/1+99e^-0.565t . According to this model, estimate how many hours it will take for three-quarters of all of the computers to contract the virus.
OpenStudy (solomonzelman):
\(\Huge\color{red}{ P(t)=\frac{25000}{1+99e^{-0.565t}} }\) right? or what?
OpenStudy (darkbluechocobo):
mhm right
OpenStudy (solomonzelman):
are you sure?
OpenStudy (darkbluechocobo):
oops meant R not P
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OpenStudy (solomonzelman):
can you draw it, please?
OpenStudy (darkbluechocobo):
\[R(t)=\frac{ 25000 }{ 1+99e ^{0.565t} }\]
OpenStudy (darkbluechocobo):
sorry i had to go for a second
OpenStudy (darkbluechocobo):
The exponent is negative and 3/4 of 25000 is 18750
OpenStudy (solomonzelman):
so re-write it with a positive exponent.
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OpenStudy (darkbluechocobo):
\[R(t)=\frac{ 25000 }{ 1+99e ^{-0.565t} }\]
OpenStudy (solomonzelman):
I am thinking of a way to re-write it with positive exponent.
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