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Mathematics 14 Online
OpenStudy (darkbluechocobo):

Help with Logistic growth function

OpenStudy (darkbluechocobo):

On a computer network of 25,000 computers, one computer spreads a vicious virus. The total number of computers on the network that contract the virus after t hours is modeled by P(t)=25000/1+99e^-0.565t . According to this model, estimate how many hours it will take for three-quarters of all of the computers to contract the virus.

OpenStudy (solomonzelman):

\(\Huge\color{red}{ P(t)=\frac{25000}{1+99e^{-0.565t}} }\) right? or what?

OpenStudy (darkbluechocobo):

mhm right

OpenStudy (solomonzelman):

are you sure?

OpenStudy (darkbluechocobo):

oops meant R not P

OpenStudy (solomonzelman):

can you draw it, please?

OpenStudy (darkbluechocobo):

\[R(t)=\frac{ 25000 }{ 1+99e ^{0.565t} }\]

OpenStudy (darkbluechocobo):

sorry i had to go for a second

OpenStudy (darkbluechocobo):

The exponent is negative and 3/4 of 25000 is 18750

OpenStudy (solomonzelman):

so re-write it with a positive exponent.

OpenStudy (darkbluechocobo):

\[R(t)=\frac{ 25000 }{ 1+99e ^{-0.565t} }\]

OpenStudy (solomonzelman):

I am thinking of a way to re-write it with positive exponent. |dw:1417640544649:dw|

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