Question

help

Answer 1

Given that f(x) = x2 − 4x − 3 and g(x) = the quantity of x plus three, over four , solve for f(g(x)) when x = 9.

−6
3
6
9


i started working on it so give me a second to post that here

Answer 2

I got this so far F(x) = x^2 - 4x - 3

f(g(x)) = (x+3/4) -4x - 3

am i on the right track?

Answer 3

no

Answer 4

Well, since you are given what x is equal to, you can just solve \(g(9)\) first, then plug whatever it is equal to, into \(f(x)\)

Answer 5

^ good plan

Answer 6

\(g(9) = \dfrac{9+3}{4} = 3\), so \(f(g(9)) = f(3) = \cdots~?\)

Answer 7

Got it? @iamabarbiegirl

Answer 8

okay so it would be like this?

f(g(9)) = f(3) = x^2 - 4x -3 ?

Answer 9

i mean f(3) = x^2 - 4x - 3

Answer 10

\[f(x) = x^2-4x-3\]
So \(f(g(9)) = f(\color{red}{3}) = \color{red}{3}^2-4(\color{red}{3}) - 3=\cdots~?\)

Answer 11

okay so
f(g(9)) = f(3) = 9 - 12 - 3

f(g(9)) = f(3) = 9 - 15

f(g(9)) = f(3) = -6