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Mathematics 17 Online
OpenStudy (anonymous):

Find the amount in a continuously compounded account for the given conditions.

OpenStudy (anonymous):

Principal: $2000 Account interest rate: 5% Time: 2 years So far I have \[\huge A=2000e^{(0.05*2)}\]

OpenStudy (anonymous):

\[A=PE ^{rt}\]

OpenStudy (anonymous):

\[\huge A=2000e^{(0.1)}\]

OpenStudy (anonymous):

that is right

OpenStudy (anonymous):

Yeah I know that. I just don't know what to do next.

OpenStudy (anonymous):

Do I just put it into a calculator?

OpenStudy (anonymous):

\[\huge e^{(0.1)} = 1.105170918076\]

OpenStudy (anonymous):

A=2210.3418361513

OpenStudy (anonymous):

^^^^ @RoseDryer

OpenStudy (anonymous):

\[\huge A=2000(1.105170918076)\] \[\huge A=2210.3418361513\] \[\huge A=$2,210.34\] I have to show my work. I'm not looking for answers.

OpenStudy (anonymous):

That's right. good job! cx

OpenStudy (anonymous):

So my next one is Principal: $400 Account interest rate: 6.7% Time: 3 years Would my equation be? \[\huge A=400e^{(0.067*3)}\] \[\huge A=400e^{(0.201)}\]

OpenStudy (anonymous):

A=489.049908729332

OpenStudy (anonymous):

I was just asking about the equation. I'm not using mathway for straight answers.

OpenStudy (anonymous):

@ganeshie8 is my equation correct for the second one

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