I need help, If anyone could please help me I'd appreciate it:) I will leave equation below.
Solve the Equation below: \[4^\left( 3x-5 \right)=256\]
Sorry
It's fine, thanks:)
I don't expect the answer, I would like to know how to solve this kind of equation.
Do you know what is the common denominator for 9/16
Nope
\(\rm \color{#20bd23}{4^{3x~-~5}~=~256}\) First you gotta take log on both sides of the equation, because we are solving for the exponent \(\rm \color{#20bd23}{log4^{3x~-~5}~=~log256}\) Do you know what to do next?
If not.. I will get back to you. I have to do something and I am not sure how long it will take
Yes:)
No worries, go ahead and do what you have to do. Thank you :)
rewrite 256 as a power to the base of 4. then, since they have the same base, make the exponents equal to each other then solve.
\(\Large \bf 4^{3x-5}=256\qquad {\color{brown}{ 2^8=256}}\qquad 4^{3x-5}=2^8\qquad x=?\)
hmmm actaullly
\(\Large \bf 4^{3x-5}=256\qquad {\color{brown}{ 4^4=256}}\qquad 4^{3x-5}=4^4\qquad x=?\)
I don't quite understand what I have to do with \[4^{3x-5}=4^{4}\]
Okay I am back
\(\rm \color{#20bd23}{4^4~=~256}\) @jackoo
okay, so since the bases are the same, 3x-5=4. solve for x
@sammixboo Okay, I understand that, @iishineontheinside oh okay
Yes, to solve for x in \(\rm \color{#20bd23}{3x~-~5~=~4}\), you first have add 5 on both sides of the equation \(\rm \color{#20bd23}{3x~-~5~+~5~=~4~+~5}\) \(\rm \color{#20bd23}{3x~=~4~+~5}\) Do you know what to do next?
Yes, I would have to divide the 3 on both sides giving me x=3
Correct :)
That would be all?:)
that would be all for the question
I see, thank you all very much:)
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